[Minor Rokka Spoilers] Rokka no Physics Part 2 - The Will of the People

Ask and ye shall receive.Part 1You wanna know how hard Adlet kicked Nachetanya in the face? Let's find out shall we?Exhibit AFirst we need to find out Nachetanya's height. The line covering Adlet here is 411px, and the line covering Nachetanya is 392px.411/392=0.95Using the height estimate we used last time, 178cm for Adlet, we'll go ahead and apply it here and calculate Nachetanya's height.178*0.95=169.1cmExhibit BI need something to use as a ruler for this thing, and what better thing to do than Nachetanya's face. Nachetanya's face is conveniently 411px like Adlet's height in the other diagram. So using the previous diagram slightly modified, the line covering Nachetanya's face is 62px.62/411=0.15178*0.15=26.7cmNachetanya's face is 26.7cm apparently. Huh. Now to go back to the scene where bunny bitch gets her just desserts, here. Adlet's foot moves from the edge of the screen to her face in 3 frames (again? what's with him and 3 frame kicks?), I'm using a 23.976FPS video for this, so my time is3/23.976=0.125sWe now know the time that Adlet took to kick her, but how far did his foot go? Well that's where my fancy triangle comes into play. You can find the resultant (the hypotenuse) by just using Pythagorean's theorem. The legs of the triangle are 445px and 771px.4452 +7712 =7178662Find the sqroot847px.So now to find the length in cm of the hypotenuse.847/411=2.0626.7*2.06=55cmAdlet's foot travels 55.02cm north-easterly in 0.125 of a second, meaning:55/0.125=440cm/s or 4.4m/s or 9.8mp/hHoly. ShitWe're not done.Divide speed by time to get acceleration.9.8m/s/0.125s=78.4m/s2Now Force=mass(acceleration). Using /u/TreeDiagram's numbers because he's a total bro,Considering your assumption that Adlet's traits are about that of an average European, his mass would be 70.8kg (156.1 lbs). One leg is 16.68% of total body weight, so it'd be (.1668)(70.8kg) = 11.81kg11.81*78.4=926NAll this is being exerted over a 0.00935m2 area as shown by /u/TreeDiagram here,Adlet kicks Hans (and Nachetanya amazingly enough) with his heel, focusing all of the force of his moving leg to his heel, average shoe size is a size 9.5-10, with the width being 110 mm, or .11m, by a length of around 8.5 cm, or 0.085m. The area is then 0.00935m2So 926N/0.0095m2 of area aka 97,473.7 Pascals, or 14PSI.The average human skull breaks at about 15PSI.He tried to kill her.If I made a mistake in my calculations, tell me please. http://ift.tt/1L1HFwT

How Hard Does Adlet Kick Hans in the Face During the Second Opening?

Well let's find out.I couldn't find details about how tall anyone in Rokka was, so I took the average height of a modern day European male (178cm) and used that for my calculations.Exhibit A(Line is slightly longer to account for the bent legs)This line is roughly 178cm, and it is exactly 610 pixels. So here we have our poor innocent Hans just chilling on his rock. Then SUDDENLY 3 FRAMES LATER THIS happens. The black line cutting off the red line leaves the red line to be 442px.442/610=0.72Multiply this by Adlet's total height, 178cm to get178*0.72=128.16cm.In other words, within 3 frames Adlet travels 178cm to kick Hans in the face. Now this is a 24 fps video, so3/24=0.125sNow you just divide the distance by the time to acquire Adlet's speed, and you get...128.16/0.125=1025.28cm/s OR 10.25m/s.Adlet is travelling at 10.25m/s aka 23mp/h before he makes contact with Hans' face.Exhibit BThis is a shot of poor Hans getting kicked and a line showing the distance he flew. This line is 610px long convenientally enough, so Hans flew 178cm within 5 frames here.5/24=0.208sDivide your distance by your time and you get your speed!178/0.208=855cm/s or 8.5m/s or 19mp/hNow to find how far off the ground Hans was sitting before he was so rudely interrupted, and you get this!. The line is 224px long.224/610=0.36178*0.36=64.08cmHans is sitting at about 64cm off the ground with his smug grin. Now to find the time Hans was in the air before he hit the ground we use the formula d=do +vo t+1/2(a)(t2 ). Where d is the total distance Hans flies, do is his original position, vo is his original position, t is time and a is acceleration (and in this case due to gravity.) Vo is 0 due to Hans just sitting at rest there, and assuming we're on Earth, gravity is -9.8m/s2.0=.64m+0m/st-4.9m(t)2Solve for t0.36sHans has an airtime of 0.36s. Now we multiply speed by time to find the total amount of distance that was covered.8.5m/s * 0.36s = 3.06m or 10 feet.SO IN CONCLUSIONIgnoring air resistance and assuming Adlet is the same height as the average European male, Adlet kicked Hans at roughly 10.25m/s or 23mp/h and Hans flew at about 8.5m/s or 19mp/h for 0.208s before falling to the ground for a total distance of around 3.06m or 10 feet.If I messed up any of my calculations, please tell me. http://ift.tt/1LHs3ZV